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5x-20+9x^2-36x=0
We add all the numbers together, and all the variables
9x^2-31x-20=0
a = 9; b = -31; c = -20;
Δ = b2-4ac
Δ = -312-4·9·(-20)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-41}{2*9}=\frac{-10}{18} =-5/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+41}{2*9}=\frac{72}{18} =4 $
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